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What Volume Of O2 Is Required? Update

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What Volume Of O2 Is Required
What Volume Of O2 Is Required

Table of Contents

What volume of O2 is needed?

Thus, the volume of O2 required to completely combust CH4 at STP condition = 0.50 mole x 22.4 L/mole = 11.20 L.

What is the volume of oxygen required to burn completely?

Thus, 585 dm3 of oxygen is required.


9.72 | What volume of O2 at STP is required to oxidize 8.0 L of NO at STP to NO2? What volume of NO2

9.72 | What volume of O2 at STP is required to oxidize 8.0 L of NO at STP to NO2? What volume of NO2
9.72 | What volume of O2 at STP is required to oxidize 8.0 L of NO at STP to NO2? What volume of NO2

Images related to the topic9.72 | What volume of O2 at STP is required to oxidize 8.0 L of NO at STP to NO2? What volume of NO2

9.72 | What Volume Of O2 At Stp Is Required To Oxidize 8.0 L Of No At Stp To No2? What Volume Of No2
9.72 | What Volume Of O2 At Stp Is Required To Oxidize 8.0 L Of No At Stp To No2? What Volume Of No2

What is the volume of O2 at 0 degrees Celsius?

Answer. 5 L of oxygen required to burn one liter of propane at 0°C.

What volume of oxygen is measured at STP?

We assume that the reaction as written proceeds quantitatively. And thus 32×0.0816⋅mol dioxygen are produced, i.e. 0.122⋅mol . At STP , an Ideal Gas occupies a volume of 22.4⋅L⋅mol−1 .

What is the volume of O2 required at 0 C and 1 atm?

Hence volume of oxygen gas measured at 0oC and 1atm, ineeded to burn completely 1L of propane gas (C3H8) under the same conditions is 5L.

What is the volume of O2 at 2.00 atm?

Volume of O2 obtained is 1. 12 Liters.

What is the volume of oxygen required to burn completely 45cm?

What is the volume of oxygen required to burn completely 45 cm3 of methane (CH4)? If 1vol/cm3 of CH4 give 2vol/cm3 of O2,then 45vol/cm3 will give 2 * 45 = 90cm3 of O2.

What volume of oxygen is required for the complete combustion of 5 cm cube of ethane?

5=12.5, so the answer is 12.5cm.

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How many liters of oxygen does STP require to burn?

Answer Expert Verified

1 mole of any gas occupies 22.4litres.


The volume of `O_(2)` at S.T.P required for completely burnt out 100 ml. of ethane is

The volume of `O_(2)` at S.T.P required for completely burnt out 100 ml. of ethane is
The volume of `O_(2)` at S.T.P required for completely burnt out 100 ml. of ethane is

Images related to the topicThe volume of `O_(2)` at S.T.P required for completely burnt out 100 ml. of ethane is

The Volume Of `O_(2)` At S.T.P Required For Completely Burnt Out 100 Ml. Of Ethane Is
The Volume Of `O_(2)` At S.T.P Required For Completely Burnt Out 100 Ml. Of Ethane Is

What volume of co2 is liberated at NTP?

Explanation: According to avogadro’s law, 1 mole of every substance occupies 22.4 L at NTP and contains avogadro’s number of particles.

What volume of oxygen is measured at 273 K?

Ans:- 0.112L 0f O2 is produced.

How many liters are in 2 mole of O2?

Assuming that the gas is at standard temperature and pressure (STP), one mole of any gas occupies 22.4 L . This means the number of moles of O2 is 222.4=0.089 mol .

What is the volume of 10.0 g of oxygen gas at STP?

Of course, at STP, dioxygen is a gas, but 10.0 g is still 10.0 g. We could calculate its volume at STP, which is 22.4 L × its molar quantity, approx. 8⋅L .

What volume does 16 g of O2 occupy at STP?

1 mole of a gas occupy =22.4L volume at STP therefore, 16gO2 gas =0.5 mole of O2 gas will occupy =10.5×22.4=11.2L at STP.

What is the volume of hydrogen gas at 273k and 1 atm?

Therefore, the answer is – option (a) – The volume of hydrogen gas is 67.2 L.

What would be the mass of oxygen gas which occupies 5.6 Litres at STP?

We get, mass =8 grams. Easy one!!!


Gram equivalent volume of O2 at STP |Saraswati Medicos|

Gram equivalent volume of O2 at STP |Saraswati Medicos|
Gram equivalent volume of O2 at STP |Saraswati Medicos|

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Images related to the topicGram equivalent volume of O2 at STP |Saraswati Medicos|

Gram Equivalent Volume Of O2 At Stp  |Saraswati Medicos|
Gram Equivalent Volume Of O2 At Stp |Saraswati Medicos|

What mass of water can be produced from 16g of methane and excess oxygen?

Since, the given weight of methane is 16 g, hence the water produced by the combustion of 16 g of methane is 36 g.

What is the volume of oxygen that is required to burn completely 45cm 3 of methane?

What is the volume of oxygen required to burn completely 45 cm3 of methane (CH4)? If 1vol/cm3 of CH4 give 2vol/cm3 of O2,then 45vol/cm3 will give 2 * 45 = 90cm3 of O2.

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